11m^2-19=0

Solution for 11m^2-19=0 equation:

11m^2-19=0

a = 11; b = 0; c = -19;
Δ = b2-4ac
Δ = 02-4·11·(-19)
Δ = 836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{836}=\sqrt{4*209}=\sqrt{4}*\sqrt{209}=2\sqrt{209}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{209}}{2*11}=\frac{0-2\sqrt{209}}{22}
=-\frac{2\sqrt{209}}{22}
=-\frac{\sqrt{209}}{11}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{209}}{2*11}=\frac{0+2\sqrt{209}}{22}
=\frac{2\sqrt{209}}{22}
=\frac{\sqrt{209}}{11}
$